Turbolet From Cape Verde, joined Nov 2007, 0 posts, RR: 1
Reply 5, posted (12 years 2 months 4 weeks 3 hours ago) and read 2327 times:
Let's put it simply, just wait till you go through 'Pure Mathematics: The Core Course for A Level'. Believe me, sometimes I have a very violent desire to tear up the bloody book! Eight months to go and then I can finally do that...
Flight152 From United States of America, joined Nov 2000, 3413 posts, RR: 6
Reply 7, posted (12 years 2 months 4 weeks 3 hours ago) and read 2346 times:
You guys are doing it all wrong.
That formula has a HUGE flaw in it. Cramer's Law doesn't apply because to this the determinates aren't exponential to y-power (or the 45X/5F Power) unless you have the cotangent (1/tangent) sub(5/3x) equaling the curve-root of the 8/3 variable (7x cubed squared). Of course you have to first square the transponent of the acquired absolute sum of both variables, then the base integer's cotangible and triceptive coordinate (in this case 8). Try using Humplestein's Law of Compression instead, DUH! Hope that helps, makes it a bit easier.
Barcode From Switzerland, joined Dec 2001, 678 posts, RR: 11
Reply 9, posted (12 years 2 months 4 weeks 1 hour ago) and read 2299 times:
*joins the anti A Level Maths crowd. I just got back from my three hour evening class and all the equations are a blur .... a perfect cube ... factorising ... laws of indices ... blah ...
Anyway, 14x - 2 = 2x + 22 is straightforward as someone pointed out. Just remember what you do to one side you should also do to the other ....
14x - 2 = 2x +22 - Add the (-2) to 22 so you get 24, and take away the 2x from the 14x to get 12x (try to get the variables on one side and the numbers on the other). So then you're left with 12x = 24, x = 24/12, x = 2.