J_Hallgren From United States of America, joined Jun 2000, 1507 posts, RR: 0 Posted (10 years 3 months 2 days 21 hours ago) and read 2699 times:

It's been 30+ yrs since high school for me so...
Need to find out how long a side of a triangle would be:
Thus starting at point A, I walk straight ahead for 50 feet to point B. I then turn right (90 degrees) and go to unknown point C.
How far should I walk to get to C if the angle from point A to C is 20 degrees off from A to B? Does that description make sense? Thanks!

Redngold From United States of America, joined Mar 2000, 6907 posts, RR: 41
Reply 1, posted (10 years 3 months 2 days 20 hours ago) and read 2696 times:

Here's all you need to know:

The Pythagorean Theorem (applies only to right triangles): a^2 + b^2 = c^2

and: All the angles of a triangle must add up to 180 degrees, if you're trying to figure out the degree of angle.

J_Hallgren From United States of America, joined Jun 2000, 1507 posts, RR: 0
Reply 3, posted (10 years 3 months 2 days 20 hours ago) and read 2690 times:

The problem with the application of P-T to this issue is that I only know the length of side A! And I need the length of side B, not the angle of the third corner, which I knew to be 70 degrees.

I also don't have any reference material to get the value of tangent for this issue, and search for it turns up way too many items.

SLC1 From , joined Dec 1969, posts, RR:
Reply 4, posted (10 years 3 months 2 days 20 hours ago) and read 2685 times:

if memory serves me correctly, and i understand your question, your length BC=50*sin20/sin70, which ultimately comes to 18.191851171331 this is because sin A/BC = sin B/AC = sin C/AB

Redngold From United States of America, joined Mar 2000, 6907 posts, RR: 41
Reply 6, posted (10 years 3 months 2 days 20 hours ago) and read 2675 times:

Argggh I didn't read the question well enough... Definitely need the sines and tangents here...

J_Hallgren From United States of America, joined Jun 2000, 1507 posts, RR: 0
Reply 7, posted (10 years 3 months 2 days 20 hours ago) and read 2673 times:

Tried Google with different phrase and found: http://www.pangolin.com/userhelp/scanangles.htm
Which deals with scanner and screen but gives the formula and value of Tangent for 20 deg as .364

Edit: I was posting this at same time FlytoEgc did so didn't see that reply but THANKS to all who helped me!