Wardialer From United States of America, joined Sep 2001, 1194 posts, RR: 0 Posted (12 years 11 months 2 weeks 3 days 23 hours ago) and read 5391 times:
OK, I'll try my best to explain this question. So bare with me.
OK, suppose an aircraft is flying at FL350 with a TAS of 450 knots and with a MAG Heading of 180 and the wind is from 270@30 knots (Crosswind). Now how could I compute the Groundspeed with a non-aviation calculator? Is there a formula for this?
Now if we say that the aircraft is flying at that heading (180) and the wind is from 360@30 knots then of course that would come out to be 480 knots GS.
TAS being 450 + Tailwind 360@30 = 480kts GS
Is there any way of figuring out the same situation for the Crosswinds? I dont have a aviation calculator so is it possible to do a formula with a standard calculator?
Inbound From Trinidad and Tobago, joined Sep 2001, 856 posts, RR: 2
Reply 1, posted (12 years 11 months 2 weeks 3 days 21 hours ago) and read 5378 times:
there's an international diagram for this.
But I have no idea on how to get it to you :-(
It's like a graph, and you enter with the difference in MAG heading, and you can read across your Headwind and Crosswind Component.
it applies to most aircraft.
hopefully someone else will figure out what I'm talking about and post it up for you.
Wietse From Netherlands, joined Oct 2001, 3809 posts, RR: 54
Reply 3, posted (12 years 11 months 2 weeks 3 days 21 hours ago) and read 5370 times:
The art of vectors.... I could calculate it for you and give you a basic formula, something with sinus, cosinus and/or tangus. But I just dont feel like it now. It is pretty easy and straight forward, you probably had had it at high school or something.
Timz From United States of America, joined Sep 1999, 7035 posts, RR: 6
Reply 5, posted (12 years 11 months 2 weeks 3 days 20 hours ago) and read 5349 times:
Let's make an insignificant revision: call Z the wind angle where zero degrees means a direct tailwind, not headwind. That requires changing the minus (in the law of cosines) to a plus. No other changes.
Ralgha From United States of America, joined Nov 1999, 1614 posts, RR: 5
Reply 6, posted (12 years 11 months 2 weeks 3 days 19 hours ago) and read 5337 times:
Sorry Timz, you're wrong. Right idea, but you got the vectors wrong.
ground speed = sqrt( 450^2 - 30^2 )
A direct crosswind to your ground track will always slow you down. You have to crab into the wind, directing some of your thrust off of your track. Since the crosswind contributes nothing to your ground track, the loss of thrust along your track reduces your speed on that track.