fritzi
Posts: 2598
Joined: Sat Jun 30, 2001 2:34 am

Math Question Help.

Wed Oct 01, 2003 7:12 pm

A friend of mine asked me if I could help her with a few math questions but my brain doesnt seem to be working very well after last night.

Could someone help me with the anwers to the following questions?

Thanks in advance!

Factor:

t^2-2t+(3/4)

Solve for x:

x^4-13x^2+36=0

 
bobrayner
Posts: 2038
Joined: Sun Apr 27, 2003 8:03 am

RE: Math Question Help.

Wed Oct 01, 2003 7:36 pm

1.
x = 1.5 or 0.5

2.
This is just a straightforward quadratic too!
Imagine x²=y; then solve y²-13y+36=0. It boils down to y=4 and y=9.
So, x=2 or x=3.
Cunning linguist
 
Andreas
Posts: 5880
Joined: Tue Oct 09, 2001 7:56 pm

RE: Math Question Help.

Wed Oct 01, 2003 7:45 pm

Bob, quite obviously you've just found another excuse to prevent yourself from gardening Big grin
I know it's only VfB but I like it!
 
fritzi
Posts: 2598
Joined: Sat Jun 30, 2001 2:34 am

RE: Math Question Help.

Wed Oct 01, 2003 7:48 pm

Thanks for the help Bob.

I owe you a beer next time you come in Vienna!



Note to self: Stop partying during the weeks!
 
fritzi
Posts: 2598
Joined: Sat Jun 30, 2001 2:34 am

RE: Math Question Help.

Wed Oct 01, 2003 10:20 pm

Sorry to pester guys you with one more question:

Solve:

(6/x)+3/(x+2) =2


The one who helps will get a beer the next time he/she comes to vienna.

Thanx
 
JAL777
Posts: 2453
Joined: Wed Jun 04, 2003 10:13 pm

RE: Math Question Help.

Wed Oct 01, 2003 10:26 pm

(6/x) + 3/(x+2) = 2

6(x+2) +3x=2(x+2)(x)

6x + 12 + 3x = 2x^2 + 4x

0=2x^2 - 5x - 12

x=4

x also has another value but I don't feel like figuring that one out right now.

[Edited 2003-10-01 15:28:13]
 
avi
Posts: 878
Joined: Sat Sep 15, 2001 1:27 am

RE: Math Question Help.

Wed Oct 01, 2003 10:32 pm

Solved by Bobrayner:

2.
This is just a straightforward quadratic too!
Imagine x²=y; then solve y²-13y+36=0. It boils down to y=4 and y=9.
So, x=2 or x=3.


If x²=y and y=4 or y=9 than x=2, x=-2, x=3 and x=-3!!!
Long live the B747
 
bobrayner
Posts: 2038
Joined: Sun Apr 27, 2003 8:03 am

RE: Math Question Help.

Wed Oct 01, 2003 10:35 pm

ok, modulo x and modulo y  Smile/happy/getting dizzy
Cunning linguist

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