- j_hallgren
**Posts:**1427**Joined:**

It's been 30+ yrs since high school for me so...

Need to find out how long a side of a triangle would be:

Thus starting at point A, I walk straight ahead for 50 feet to point B. I then turn right (90 degrees) and go to unknown point C.

How far should I walk to get to C if the angle from point A to C is 20 degrees off from A to B? Does that description make sense? Thanks!

Need to find out how long a side of a triangle would be:

Thus starting at point A, I walk straight ahead for 50 feet to point B. I then turn right (90 degrees) and go to unknown point C.

How far should I walk to get to C if the angle from point A to C is 20 degrees off from A to B? Does that description make sense? Thanks!

COBOL - Not a dead language yet!

Here's all you need to know:

The Pythagorean Theorem (applies only to right triangles): a^2 + b^2 = c^2

and: All the angles of a triangle must add up to 180 degrees, if you're trying to figure out the degree of angle.

The Pythagorean Theorem (applies only to right triangles): a^2 + b^2 = c^2

and: All the angles of a triangle must add up to 180 degrees, if you're trying to figure out the degree of angle.

Up, up and away!

- MD11Engineer
**Posts:**13916**Joined:**

Quickly I would say:

Alpha = Angle between AC and AB

AB = distance A to B

BC = distance B to C

BC = tan (Alpha) * AB

Jan

Alpha = Angle between AC and AB

AB = distance A to B

BC = distance B to C

BC = tan (Alpha) * AB

Jan

Je Suis Charlie et je suis Ahmet aussi

- j_hallgren
**Posts:**1427**Joined:**

The problem with the application of P-T to this issue is that I only know the length of side A! And I need the length of side B, not the angle of the third corner, which I knew to be 70 degrees.

I also don't have any reference material to get the value of tangent for this issue, and search for it turns up way too many items.

[Edited 2005-05-31 15:41:38]

I also don't have any reference material to get the value of tangent for this issue, and search for it turns up way too many items.

[Edited 2005-05-31 15:41:38]

COBOL - Not a dead language yet!

if memory serves me correctly, and i understand your question, your length BC=50*sin20/sin70, which ultimately comes to 18.191851171331 this is because sin A/BC = sin B/AC = sin C/AB

[Edited 2005-05-31 15:46:30]

[Edited 2005-05-31 15:46:30]

We're gonna do what we like to call a "jetBlue how do you do", which is slang for dumping a bunch of fuel in the ocean

You know the angle BAC to be 20 degrees.

Tan (angle) = opposite side / adjacent side

So if your unknown side BC = x, you would do:

Tan 20 = x / 50

So x = 50 * Tan 20

Which should give you an answer of 18.19851171 ft...

Tan (angle) = opposite side / adjacent side

So if your unknown side BC = x, you would do:

Tan 20 = x / 50

So x = 50 * Tan 20

Which should give you an answer of 18.19851171 ft...

Come fly with me, let's fly, let's fly away...

Argggh I didn't read the question well enough... Definitely need the sines and tangents here...

Up, up and away!

- j_hallgren
**Posts:**1427**Joined:**

Tried Google with different phrase and found:

http://www.pangolin.com/userhelp/scanangles.htm

Which deals with scanner and screen but gives the formula and value of Tangent for 20 deg as .364

Edit: I was posting this at same time FlytoEgc did so didn't see that reply but THANKS to all who helped me!

[Edited 2005-05-31 15:58:48]

http://www.pangolin.com/userhelp/scanangles.htm

Which deals with scanner and screen but gives the formula and value of Tangent for 20 deg as .364

Edit: I was posting this at same time FlytoEgc did so didn't see that reply but THANKS to all who helped me!

[Edited 2005-05-31 15:58:48]

COBOL - Not a dead language yet!