To those starting a fight over something very basic-
the formula I gave you is the only one that can explain the most simple graph in the study of turboreactors. i.e. the Thrust vs Velocity graph.
please note that this formula is only valid in subsonic airflows, so don't use the F16 as an example in this...
Have you ever seen this graph?
Good. If not, I'll try to describe it to you.
It looks like this:
If you set the thrust on the vertical axis and the speed on the horizontal exis, you'll find the representation of thrust produced by an engine running in a constant regime at a given altitude to be a more or less horizontal line sloping slightly downwards if you accelerate (move to the right in the graph), till around 250kts or M.4 where the thrust line will once again start to move upwards to reach around the same value it had at zero speed!
from the formula I gave you:
F = Dm x (Vjet-TAS)
F = Dm X vjet - Dm x TAS
if your TAS becomes bigger, you substact more in the formula from Dm x vjet, so the thrust gets smaller.
As from 250kts the compressability of the air starts to take effect and although the Dm x TAS still gets bigger all the time, so does the DM x vjet thanks to an increase in Dm, resulting in an small overall increase in thrust to around the initial value.
In general it can be said that an engine running at a constant altitude (for instance MSL) is producing a same specific ammount of thrust for any given power setting at two different speeds.
For maximum thrust (which is also a specific amount of thrust, isn't it?) these two different speeds are:
TAS = 0kts or M.0
TAS = between M0.65 and M0.90 depending on the engine.
This is ideal since the first speed corresponds with the take-off phase (a lot of thrust needed).
The second speed is made by the engine manufactorer to correspond with the cruising speed. Since we normally don't need the maximum available thrust in this case, it allows for the selection of a lower thrust setting and thus a lower fuel flow.
However, in emergency situation like an engine failure, it gives you the chance to get a lot of thrust (called max continuous thrust then due to some EGT limitations) which will allow you to drift down to a lower altitude at only a very slow rate of descent giving you the biggest possible distance to evercome any mountaneous obstacles on you drift down path.
You see, both of you were more or less correct in a way. If two people have a different idea it does not automatically mean one of them must be wrong you know...